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Saturday, October 23, 2010

LEVEL 43 JANET


While our long absence from the blog, many cried and begged for the next levels solutions 43 and up, well we're starting to puvlish them, after reordenring the blog a little, we're still missing three other paths besides this one, we'll publish them as long as we solve them. For now....

WELCOME TO THE FRIDGE!!!

Inthis level you get to a room freezed by a stuck air conditioner, which has such a low temperature that has frozen the door and it's locked. You have to find the way in which you could rise the temperature,but..... HOW????

Again, we're very sorry but you'll have to use math once more. A strange weird friend left you a clue on the wall, remember Giskard? the nerd & geeky man that has left strange clues all over?

Look at this hint:


He left you and equation:

32 = 273,15

? = 293,15

Since we're dealing with temperatures, let's think a little:

  • In which temperature scale is 32 a very low temperature?
  • In which temperature scale is 273,15 a very low temperature?
  • In which temperature scale is 293,15 a reasonable not too hot not too cold temperature?

Hoping you have thought contiously about it you'll deduct that normally 273,15 degrees is a very HOT temperature in fahrenheit and celsius, what you've got?

KELVIN

Now you know you can find out 273,15 degrees kelvin are equal to ? celsius or ? fahrenheit, in which of the two scales is 32 = 273,15 once you got the answer, convert 293,15 to that scale and you'll get the answer.

For the lazy ones

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1 comment:

  1. When you click on the panel, the title says "? =". Where have you seen that before?

    http://ebony.extra.hu/zelda/level0037.html

    ...and what did o equal? Enter that to get a Mystic Marvel.

    http://ebony.extra.hu/janet/unknown/8.html

    ReplyDelete

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